An air puck of mass m1 0.30 kg is tied to a string and allowed to revolve in a c

Question

An air puck of mass m1 0.30 kg is tied to a string and allowed to revolve in a circle of radius R 1.4 m on a frictionless horizontal table. The other end of the string passes through a hole in the center of the table, and a mass of m2 = 1.2 kg is tied to it (see the figure below). The suspended mass remains in equilibrium while the puck on the tabletop revolves. (a) What is the tension in the string? IN (b) What is the horizontal force acting on the puck? IN (c) What is the speed of the puck? m/s

Explanation / Answer

Using Force balance in Horizontal circular motion

Fnet = F1 - Fc = 0

Fc = centripetal force

F1 = m1*V^2/R

Now Using force balance in vertical direction:

Fnet = T - m2*g = 0

T = m2*g

T = Tension in string = 1.2*9.81

T = 11.77 N

Part B.

Since hole in the center of table is frictionless, So

T = F1

F1 = Horizontal force on puck = 11.77 N

Part C

F1 = m1*V^2/R

V = sqrt (R*F1/m1)

V = sqrt (1.4*11.77/0.30)

V = 7.4 m/sec

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