An atom of 2ecays by a emission. If the emitted a particle carries Particle Mass

Question

An atom of 2ecays by a emission. If the emitted a particle carries Particle Mass (u) away 100% of the released energy as kinetic energy, how fast is it moving? The masses of an electron, an alpha particle, and several neutral isotopes are given, in terms of atomic mass units, to the right. 5.4858 x 104 .001506179125 207T 206.977419429 208T 207.9820187 209T 208.98535895:2 21Pb 210.988736964 212Pb 211.991897543 211Bi 210.98726946 212Bi 211.991285724 213 212.994384666 214Bi 213.998711539 215Bi 215.001769776 215Po 214.999419988 216po 216.001915035 218AL |218.008694336 Number m/s At 219.011161691 22Fr 222.01755173 223Fr 223.019735857 227Ac227.027752127 28Ac 228.031021112

Explanation / Answer

From the given data,
delta_m = m_AC - (m_Fr + m_alfa)

Energy released in th reaction, E = ( m_AC - (m_Fr + m_alfa) )*931.5 MeV

= (227.027752127 - (223.019735857 + 4.001506179125))*931.5 MeV

= 6.064 MeV

= 6.064*10^6*1.6*10^-19 J

= 9.70*10^-13 J

given KE = E

we know,

KE = (1/2)*m*v^2

v = sqrt(2*KE/m)

= sqrt(2*9.70*10^-13/(4.001*1.66*10^-27))

= 1.71*10^7 m/s <<<<<<<-----------------Answer

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