Three charges are positioned as indicated in the figure. a. what are the magnitu

Question

Three charges are positioned as indicated in the figure.
a. what are the magnitude and direction of the electric field at the position of the +15 uC charge due to the other two charges.
b. what are the magnitude and direction of the net force exerted on the +15uC charge by the +11uC and +13 uC charges.
c. if the 11uC charge was brought to this position from infinity, what was the work done to place it here?
d. what was the electric potential at this position before the 11uC charge was placed there?

1. Three charges are positioned as indicated in the figure. (ke-8.99 10* N-m/C) +15 IC u- 0.075 37° +13 uc-0.10m+11 IC horizontal E A vertical are the magnitude and direction of the electric field at the position of the +15 uC ce exerted on the +15 uc charge by b. What are the magnitude and direction of the net for c. If the 11 uC charge was brought to this position from infinity, what was the work done to d. what was the electric potential at this position before the l charge was placed there? charge due to the other two charges? the +1 l pC and +13 ? C charges? place it here?

Explanation / Answer

Distance between 15 and 11= sqroot (0.075^2+ 0.10^2) = 0.125 m

a) Ex= K ( 11 x 10^-6) cos 37 / 0.125^2 = 5060.16 x 10^3 N/C

Ey = K ( 11 x 10^-6) sin 37 / 0.125^2 + K (13 x 10^-6 ) /0.005625 = 24613. 1 x 10^ 3 N.C

E = sqroot ( Ex^2 +Ey^2) = 25127.864 x10^3 N/C

b) F = qE =15 x 10^-6 (  25127.864 x10^3 ) = 376.93 N

c) PE of system = K ( 13 x 10^-6 x 11x 10^-6 ) /0.10 + K (13 x 10^-6 x 15x 10^-6 ) /0.075 + K (11x 10^-6 x 15 x 10^-6) /0.125 = 9 x 10^ -3 ( 1430 +2600+1320)=48.15 J

d) K ( 13 x 10^-6) ( 15x 10^-6 )/0.075 = 23.4 J

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