Three charges (q1 = 7.6 ?C, q2 = -4.7 ?C, and q3 = 1.1?C) are located at the ver

Question

Three charges (q1 = 7.6 ?C, q2 = -4.7 ?C, and q3 = 1.1?C) are located at the vertices of an equilateral triangle with side d = 6.1 cm. q1 is on the bottom left, q2 is on the bottom right, and q3 is at the top. A charge q4 = 1.1 ?C is now added. (This is below q1 and q2 so that q1, q2, and q4 create another equilateral triangle where the point (q4) is at the bottom. So, basically, there are two equilateral triangles that form a diamond--q1 and q2 on the left and right, q3 as the top point, q4 as the bottom point). 1) What is F2,y, the y-component of the new net force on q2 2) What is F1,x, the x-component of the new net force on q1 I answered the other three parts of this question, now I am stuck and these 2.

Explanation / Answer

forces on q2 = y component = -F32sin60 j + F42sin60 j

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