Sodium ions (Na+) move at 0.850 m/s through a blood stream in the arm of a perso
ID: 2041243 • Letter: S
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Sodium ions (Na+) move at 0.850 m/s through a blood stream in the arm of a person standing near a large magnet. The magnetic field has a strength of 0.257 T and makes an angle of 47.0degrees with the motion of the sodium ionsm the arm contains 95.0 cm3 of blood with 3.00X10^20 Na+ ions per cubic centimeter. If no other ions were present in the arm, what would be the magnetic force on the arm?
tudent/Assignment-Resp it?dep 17876722 s SerCPT 19.P.008 An electron is accelerated through 2450 V from rest and then enters a region where there is a uniform 1.70 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron? (a) maximum VN (b) minimum VN -/10 points SerCP7 19 P010 soln Ask Your Tea Sodium ions (Na) move at o.850 m/s through a bloodstream in the arm of a person standing near a large magnet. The magnetic field has a st of 47.09 with the motion of the sodium ions. The arm contains 95.0 cm3 of bloo the magnetic force on the arm d with 3.00 x 1020 Na ions per cubic centimeter. If no other ions were present in the arm, what would b + 1010 points I Previous Answers SerCP7 19 P009 soln My Notes Ask Your Te gnetic field B at 2.0 x 10 m/s and exhibits an acceleration of 2.0 x 10 leration of 2.0 x 1013 m/s2 in the +x-direction when its velocity is in the +2-directio m/st in the +x-direction w Determine the magnitude and direction of the field 00104 T-y direction Type here to search 9:02 PExplanation / Answer
charge of Na+ ion is 1.6 *10^-19 C
no of ions N = 3*10^20 * 95 = 2.85 *10^22 ions
magnetic force F = qv B sin theta
F = 1.6*10^-19 * 0.850 * 0.257 sin 47
F on one ion = 0.255 *10^-19 N
Force on N ions = N * 0.255 *10^-19
F total = 2.85*10^22 * 0.255*10^-19
Ftotal = 726.75 N
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