Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Cengage \\ e Search Textbook Solutio X1 e Search Textbook Solutio/X / Chapter 19

ID: 2041319 • Letter: C

Question

Cengage e Search Textbook Solutio X1 e Search Textbook Solutio/X / Chapter 19 × G A proton moving freely X Cwww.webassign.net/web/Student/Assignment-Responses/submit?dep 17876956 Apps ? Bookmarks fy paper rating drive D chem c 1,1,1-TRIFLUOROPRC ? blackboard??lemonade L hair O biochem kelsey Other bookmark O repelled attracted 17. 0/10 points| Previous Answers SerCP7 19.P047.soln My Notes Ask Your Teach What current is required in the windings of a long solenoid that has 800 turns uniformly distributed over a length of 0.420 m in order to produce a magnetic field of magnitude 1.00 x 10 4 T at the center of the solenoid? 00417 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. mA Submit AnswerSave Practice Another Version 18. -/12 points OSColPhys1 22.4.001 My Notes Ask Your Teach What is the direction of the magnetic force on a negative charge that moves as shown in each of the six cases shown in Figure 21.46? Boa 10:23 PM O Type here to search 4/15/2018

Explanation / Answer

Given,

n = 800 ; L = 0.42 ; B = 1 x 10^-4 T

We know that, the magnetic field of a solenoid is given by:

B = u0 (n/L) I

I = B/u0 (n/L) = B L/(u0 n)

I = 1 x 10^-4 x 0.42/(4 x 3.14 x 10^-7 x 800) = 0.0418 A

Hence, I = 0.0418 A = 41.8 milli Ampere

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote