Cengage * Y CVLv2 I Online teaching 8 – nx CO west.cengagenowcom/irn/takeAssignm

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Cengage * Y CVLv2 I Online teaching 8 – nx CO west.cengagenowcom/irn/takeAssignmenttakeCovalentActivitydo?locator-assignment-take&takeAssignmentSessionLocator-assignment-take; Q fo: Chapter 14: EOC References Question 2 o 1 pt What quantity (moles) of HCl) must be added to 10L of 5.0 M NaOH to achieve a pH of 0.00? (Neglect any volume changes) Question 22 o 1 pt mol HCL - mol Question 23 0 1 pt Submit Answer Try Another version 10 item attempts remaining Ouestion 24 1 pt Question 26 1 pt Question 26 1 pt Question 27 o 1 pt Question 28 1 pt Question 29 0 1 pt Question 30 1 pt Question 31 O 1 pt Question 32 1 pt Question 33 o 1 pt Question 34 1 pt Ouestion 35 1 pt Question 36 1 pt Progress 22/61 items Due Nov 1 at 11:55 PM Previous Next Hinish Assignment Email InstructorSave and Fxit 3:18 PM EO Type here to search AE 11/1/2011 9

Explanation / Answer

we have below equation to be used:

pH = -log [H+]

0 = -log [H+]

log [H+] = -0

[H+] = 10^(-0)

[H+] = 1 M

since volume of solution is 1 L

At the end there should be 1 mol of H+ remaining

moles of NaOH reacting = molarity * volume

= 5.0 M * 1.0 L

= 5 mol

So, we must add 6.0 mol of HCl

5.0 mol of this will react and 1 mol will remain

Answer: 6.0 mol

Feel free to comment below if you have any doubts or if this answer do not work

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