Two positive charges of 10 µC are placed at two corners of an equilateral triang

Question

Two positive charges of 10 µC are placed at two corners of an equilateral triangle with each side of length 30 cm. A negative charge of -2 µC is placed at the third corner. (Assume that all electric potentials and potential energies are zero at infinity)
(a) What is the potential energy of the negative charge? J
(b) How much work would you have to do to remove the negative charge to infinity (a long distance away)? J

Explanation / Answer

a) the plate which is at 1000 V is positively chrged b) v = e.d => 1000 = E.(2/1000) E = 2*106 volt/m from +ve plate to -ve plate , toward plate which is grounded c) potential = work done to carry -ve charge half the way = (1/1000)*(4)*(10-6)*(2*106) = -0.008 J if -ve charge is picked from -ve plate and tried to move towards + plate half the way d) it hits the +ve plate e) chnage in P.E = change in K.E (1/2)*(1/1000)*v*v = 8/1000 v*v = 16*106 v =4 m/sec

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.