Two positive charges of 1.1e-10 C are placed on the x axis at distances +18 cm a

Question

Two positive charges of 1.1e-10 C are placed on the x axis at distances +18 cm and -18 cm from the origin, respectively. A third positive charge of 5e-11 C can be moved along the y axis. At what value of y the electrostatic force on the third charge is maximal?

Explanation / Answer

F = 2 (k q1 q2/r^2) cos? >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> F = 2*(9e9*1.1e-10*5e-11/r^2) (y/r) >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> F = 0.99e-10 (y/r^3) >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> r = (18*18 + y^2)^(0.5) >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> F = 0.99e-10 (y/(18*18 + y^2)^(3/2)) >>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>> ymax = 9 ?2 = 9 * 1.4142 = 12.7 cm

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