Determine the magnitude of the force between two point charges, Q1 = -2e located

Question

Determine the magnitude of the force between two point charges, Q1 = -2e located at (-3.60 cm, +4.10 cm) and Q2 = -8e located at (-0.60 cm, -8.60 cm). Give your answer in the form "a.bc x 10^(y) N".

I have the answer for the magnitude now I need to find the direction of the force and give the answer in the form of abc.d degrees clockwise from the positive x axis direction and round to the nearest tenth of a degree. Please help

Continue working the problem in #2 above by calculating the direction of the force that Q1 exerts on Q2. Give your answer in the form "abc.d" degrees, clockwise from the +x axis direction, and rounded to the nearest tenth of a degree.

work in detail so I can understand and be able to work future problems pleeease

Explanation / Answer

Two charges are both negative, so the direction of the force that Q1 exerts on Q2 is from Q1 to Q2.
The vector of Q1 to Q2 is <-0.60, -8.60> - <-3.60, +4.10>
= <3.00, -12.70>
the required angle = tan-1(12.70/3.00) = 76.7o

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