1) C=(A^2+B^2-2ABcos(c)) 2) b=sin -1 (Bsin(c))/C 3) C x =A+Bcos 4)C y =Bsin Whic

Question

1) C=(A^2+B^2-2ABcos(c))

2) b=sin-1(Bsin(c))/C

3) Cx=A+Bcos

4)Cy=Bsin


Which of the following sets of conditions, if true, would show that Equations 1 and 2 above define the same vector as Equations 3 and 4?

length and direction for . length and x component for . direction and x component for . length and y component for . direction and y component for . x and y components for . 1) C=root (A^2+B^2-2ABcos(c)) 2) b=sin-1(Bsin(c))/C 3) Cx=A+Bcostheta 4)Cy=Bsintheta Which of the following sets of conditions, if true, would show that Equations 1 and 2 above define the same vector as Equations 3 and 4? length and direction for C. length and x component for C. direction and x component for C. length and y component for C. direction and y component for C. x and y components for C.

Explanation / Answer

Remember that a vector is quantity that has magnitude and direction.

There are 4 answers above which are equivalent:

lenghth and direction is the same thing as saying magnitude and direction.

Direction and x-component

Direction and y-component

x and y component

The reason that the others are not valid is because say you are given the length and x-component in the first quadrant. If you flip that same vector about the x-axis, it will have the same x-component and the same length, but different value of y. As a matter of fact you would get -y.

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