1) C3H8 + 5 O2 ---> 3 CO2 + 4 H2O Now this balanced equation tells us most of wh

Question

1) C3H8 + 5 O2 ---> 3 CO2 + 4 H2O

Now this balanced equation tells us most of what we need to know.

We need 1 mole of oxygen for every 5 moles of oxygen.

Treating propane and oxygen as an ideal gas and assuming STP.

1 mole = 22.4 liters of both gasses if we treat them as an ideal gas.

Thus for every 1 ml of propane you need 5 ml of oxygen. Thus if you have 3.5 ml of propane you need 17.5 ml of oxygen.

2) a) moles = wieght / molar mass = 3.71 / 64 = 0.058

b) moles = wieght / molar mass = 165 / 18 = 9.167

c)  moles = wieght / molar mass = 0.1 / 164 = 6.1e-4

Explanation / Answer

1. What volume of oxygen is required to bum 3.500 ml of propane in the following combustion reaction, assuming that both gases are measured at the same temperature and pressure? C3H3(g) + 502(g) + 3 CO2(g) + 4H,O(g) 2. Calculate the amount, in moles, of (a) 3.71 g Cu, (b) 165 g H0, and (c) 0.100 g Ca(NO3)2. Consider the combustion burninol af nronana (al How many males of Coare formed wh

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