For a sound wave of wavelength lambda, you have a waveguide running in the xy pl
ID: 2045497 • Letter: F
Question
For a sound wave of wavelength lambda, you have a waveguide running in the xy plane at y = -r. There is an optional path for the sound in the range -2r x 2r. This path is described by the following equation. y(x) = Show that the minimum length of the optional path that results in fully destructive interference is given when r = lambda / 4 (pi - 2). Do you think a better path would be a Gaussian like y(x) = (r + 1)e-x2 - r? Or perhaps a sine curve like y (x) = r cos x, (-pi x pi)? Justify your answer, Take a moment and consider noise-cancelling headphones. Comment.Explanation / Answer
This question is from University Physics with Modern Physics Book 13th Edition. Here's the link that shows all the problems solved for this book for every chapter. Find your problem and see the solution. http://www.cramster.com/solution/solution/1252059 Rate
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