You have a lightweight spring whose unstretched length is 4.0cm . You\'re curiou
ID: 2045919 • Letter: Y
Question
You have a lightweight spring whose unstretched length is 4.0cm . You're curious to see if you can use this spring to measure charge. First, you attach one end of the spring to the ceiling and hang a 3.0g mass from it. This stretches the spring to a length of 5.5cm . You then attach two small plastic beads to the opposite ends of the spring, lay the spring on a frictionless table, and give each plastic bead the same charge. This stretches the spring to a length of 4.5cm .What is the magnitude of the charge (in nC ) on each bead?
Explanation / Answer
You have a lightweight spring whose unstretched length is 4.0 cm. You're curious to see if you can use this spring to measure charge. First, you attach one end of the spring to the ceiling and hang a 1.0 g mass from it. This stretches the spring to a length of 5.0 cm. You then attach two small plastic beads to the opposite ends of the spring, lay the spring on a frictionless table, and give each plastic bead the same charge. This stretches the spring to a length of 4.5 cm. F=k(q1q2)/r^2 However there is a problem with the statement of the problem 1. Determine a DFDFDSF DSD ASDASDADS sdfddff In general the force between two charges can be defined as F=u(q1q2)/r^2 u - universal constant q1, q2 - point charges r – distance between them And the force that stretches the string is F=kx Then electric force must be equal to electric force u(q1q2)/r^2=kx Then q1q2= kx r^2 / u Since both charges are hopefully the same then q=sqrt(k x r^2 / u) x since x1=5cm when .oo1 kg stretched it we have k=mg/x1= .001 9.81/.05= 0.1962 N/m the u= 8.988×109 N m^2 /C^2 Then the q=sqrt(k x r^2 / u) becomes (r=unstretched + stretched part of the spring) q=sqrt(0.1962 N/m .045 (.045m + .04m)^2 /8.988×109 N m^2 /C^2 ) = q=sqrt(7.097E-15) q=8.42 E-8 Coulombs or C
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