In the figure, the current of the circuit in the 8 resistor is 1.42 A. What is t
ID: 2047422 • Letter: I
Question
In the figure, the current of the circuit in the 8 resistor is 1.42 A. What is the current in the 2 resistor?
It's been a while since I had physics lecture, so if you can lead me to the answer, I'd be grateful.
Explanation / Answer
The two common endpoints of 16 & 8 ohm resistor is at a potential difference say V. V= C x R =1.42 x 8 = C x 16 = > C = 1.42 x 8 / 16 = 0.71 A. (C is denoted here as current) So current in the top loop is 0.71 + 1.42 = 2.13 A equiv resistance of top is : 16 // 8 ~ 16 x 8 /(16 + 8) = 16 x 8 /24 = 16/3 ohm 20 in series with it is ~ 16/3 + 20 = 76/3 ohm lower box has resistance : 6//8 ~ 6x8/(6+8) = 48/14 = 24/7 ohm so we have top // bottom 76/3 // 24/7 so current in lower part of circuit is : 2.13 x 76/3 = C x 24/7 = > C = 2.13 X 76/3 X 7/24 ~ 15.74 A So 6 // 8 so current divides in the inverse ratio to the resistor : 15.74 * 6 / (2+6) = 11.8 A. Have a good day !!
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