A 1.83 kg disc is attached to the end of a string whose length is 0.530 m. The d

Question

A 1.83 kg disc is attached to the end of a string whose length is 0.530 m. The disk slides without friction on a horizontal surface as indicated in the Figure. If the string can withstand a maximum tension of 64.5 N, a) what is the maximum tangential speed the disk can have before the cord break?

b) The disk is whirled in a vertical circle of the same radius about a fixed point. Find the tension at the top if the speed at the top is 4.17 m/s.

A 1.83 kg disc is attached to the end of a string whose length is 0.530 m. The disk slides without friction on a horizontal surface as indicated in the Figure. If the string can withstand a maximum tension of 64.5 N, a) what is the maximum tangential speed the disk can have before the cord break? b) The disk is whirled in a vertical circle of the same radius about a fixed point. Find the tension at the top if the speed at the top is 4.17 m/s.

Explanation / Answer

mass= 1.83 kg

L = 0.53 m, maximum T = 64.5 N

So,

a) maximum tangential speed = v [say]. Then, mv2/L = T.

So, 1.83 x v2 = 64.5 x 0.53

So, v = 18.68 = 4.32 m/s

b) speed at top = 4.17 m/s.

SO, at top, mv2/L - mg = T.

SO, T = m(v2/L -g) = 1.83 x ( 32.80 - 9.81) = 42.08 N

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