A 1.810 kg block of wood rests on a steel desk. The coefficient of static fricti

Question

A 1.810 kg block of wood rests on a steel desk. The coefficient of static friction between the block and the desk is ?s = 0.655 and the coefficient of kinetic friction is ?k = 0.205. At time t = 0, a force F = 7.15 N is applied horizontally to the block. State the force of friction applied to the block by the table at the following times: t=0 and t>0

Consider the same situation, but this time the external force F is 14.4 N. Again state the force of friction acting on the block at the following times: t=0 t>0

Explanation / Answer

innitially the blcok does not moves 2)a={14.4-(1.81)(10)(.205)}/1.81=10.6/1.81=5.9 =...kinetic friction acts

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