You are on a space station. You are in a room with normal earth-like gravity (10

Question

You are on a space station. You are in a room with normal earth-like gravity (10 m/s2). You are to determine and E-field in the room because when you "drop" a charge, it has moved foward a distance by the time it reached the ground. Here's your data:

- Particle's mass is 125 micrograms.

- Particle's charge is 30 nanocoulombs.

- The initial velocity of the particle in x and y are both 0.0 meters per second (at rest).

- The particle's initial height above the ground was 1.4 meters.

- The particle moved foward 5 meters by the time it hit the ground.

- The E-field is parallel to the floor.

What is the E-field of the room? What is the final speed of the particles? Any help is greatly appreciated!

Explanation / Answer

Time taken by the mass to reach the ground = sqrt(2H/g)
= 0.53 sec

In this time it travelled 5 m in horizontal direction...
Let electric field be E.
Acceleration, a = F/m = qE/m
From equation of motion,
S = at2/2 = S = qEt2/2m ; [Since initial velocity is 0m/s.]
E = 2Sm/qt2
= (2*5*125*10-6)/(.53*.53*30*10-9)

= 37.08*103 N/C.

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