Consider two protons separated by a distance of 1.0 X 10^-12 m. (a) What is the

Question

Consider two protons separated by a distance of 1.0 X 10^-12 m.

(a) What is the gravitational force of attraction between the protons?

(b) What is the electric force of repulsion between these protons? What is the ratio of the electric force and the gravitational force?

(c) Consider a second pair of protons separated by a larger distance, so their electric repulsion matches the gravitational attraction of the other, closer pair calculated in part (a). How far apart would these protons have to be?

Explanation / Answer

Mp = 1.67x10^-27 kg a) The gravitational force between two objects is; F = G*m1*m2/r^2 Where G = 6.673x10^-11 N*m^2/kg^2 So, the force is: Fg = G*Mp*Mp/r^2 = 6.673x10^-11 * 1.67x10^-27 * 1.67x10^-27 / 10^-24 = Answer b) Electric force of repulsion between these protons Fe = kQ1Q2 / r^2 Fe = answer ratio = Fe/Fg = kQ^2 / Gm^2 = Answer c)

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