(a) Determine the velocities of the two objects just after the collision. (Indic
ID: 2050217 • Letter: #
Question
(a) Determine the velocities of the two objects just after the collision. (Indicate the direction with the sign of your answer. Take the positive direction to be to the right.)v1 = 1 m/s v2 = 2 m/s v1 = 1 m/s v2 = 2 m/s
Explanation / Answer
Mass 1 hits mass two with velocity u mgh = .5 m u^2 => gh = .5 u ^2 => u = 7.86 m/sec Conserve momentum m1 u1 + m2 u2 = m1 v1 + m2 v2 => .450 * 7.86 + 0 = .450 v1 + v2 => .450v1+ v2 = 3.536 ---- eqn 1 => v2 = 3.536 - .450v1 Conserve energy .450* 7.86^2 = .45 * v1^2 + 1 * v2^2----- eqn 2 put value of v2 in eqn 2 (12.5032 - 27.8)+ (.2025 + .45)v1^2 - 3.1824v1= 0 v1 = 7.86 , - 2.98 we select -2.98 as we see block 1 moves left after collision put v1 in eqn 1 v2 = 4.877 m/sec
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