A 40.5 \\Omega resistor and a 91.8 \\Omega resistor are connected in parallel, a

Question

A 40.5 Omega resistor and a 91.8 Omega resistor are connected in parallel, and the combination is connected across a 120 { m V} dc line.

Part A-
What is the resistance of the parallel combination?
R = ______________________________________O

Part B-
What is the total current through the parallel combination?
I = _______________________________________A

Part C-
What is the current through the 40.5 Omega resistor?
I(1)= ______________________________________A

Part D-
What is the current through the 91.8 Omega resistor?
I(2) = _______________________________________A

Explanation / Answer

a) 40.5*91.8 / (40.5+91.8) = 28.1 O b) I =V/R = 4.27 A c) I = V/R1 = 2.96A for 40.5 O d) I =V/R2 = 1.307 A

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