A car comes to a bridge during a storm and finds the bridge washed out. The driv

Question

A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to try leaping it with his car. The side the car is on is 19.4 m above the river, whereas the opposite side is a mere 1.3 m above the river. The river itself is a ranging torrent 60.0 m wide. The car is at 31.2 m/s to be traveling as it leaves the cliff in order to just clear the river and land safely on the opposite side. What is the speed of the car just before it lands safely on the other side?

Explanation / Answer

time for which car is in the air for vertical motion ( u=0) 2as=ut+0.5*a*t^2 2*9.8*(19.4-1.3) =0+0.5*9.8*t^2 354.76 =4.9*t^2 t^2=72.4 t =8.51 seconds vertical velocity component v=u+at v=0 +9.8*8.51 v =83.398 m/s distance travelled horizontally s =8.51*31.2 =265.47 m so speed of the car =sqrt(31.2^2 +83.398^2) =sqrt(7928.67) =89.04 m/s ( answer)

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