Frightarrow and rrightarrow are vectors. Frightarrow = Fxi^ + Fyj^ + Fzk^, where

Question

Frightarrow and rrightarrow are vectors. Frightarrow = Fxi^ + Fyj^ + Fzk^, where Fx = 55.1 N, Fy = 60 N, and Fz = -70N, and rrightarrow = xi^ + yj^ + zk^, where x = 40 m, y = -21.0 m, and z = -10 m. Give your answer to three significant figures. What is the magnitude of Frightarrow (N)? What is the magnitude of rrightarrow (m)? What is the x component of the vector product rrightarrow times Frightarrow (N m)? What is the y component of the vector product rrightarrow times Frightarrow (N m)? What is the z component of the vector product rrightarrow times Frightarrow (N m)?

Explanation / Answer

a. Magnitude of F = (55.12+602+(-70)2) =11536.01 = 107.4 N

b. Magnitude of r =(402+(-21)2+(-10)2) =2141 = 46.27 m

c. x - component of vector product of r & F = 60*(-10)- (-70)*(-21) = -2070

d. y - component of vector product of r & F = (-70)* 40 - 55.1*(-10) = -2249

e. z - component of vector product of r & F = 55.1*(-21) - 40*60= 3557.1

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