the first two please. An insulating rod having linear charge density lambda = 40

Question

the first two please.

An insulating rod having linear charge density lambda = 40.0 mu Cm and linear mass density mu = 0.100 kg/m is released from rest in a uniform electric field E = 200 V/m directed perpendicular to the rod at shown in the figure on the right. What is the potential energy of the rod at distance d downfield? Answer using the symbol lambda, I,E, and d. If the current position of the rod has the electric potential V = 0. what is the electric potential at distance d (= 2 00 m) downfield Use only symbols given. Kind the velocity numerically. If at distance d downfield the velocity of the rod is v, what is the kinetic energy? Please show and provide all steps few calculations, formulas, work, and answer question completely for full credit, Thank you! PS: If you are sending images please make them readable.

Explanation / Answer

Please ask if you have any doubt.I will help you.

= 40C/m

= 0.100 kg/m

E = 200V/m

Note the answers are done assuming L,d in meters.

Electric potential is given by :

Vd = 0 - Ed = -200d V

1) The potential energy of the rod at d : QVd

P.E = -LEd

P.E = (40C)(L)(-200d) = -8Ld (10-3)Joules

" -ve" because potential energy decreases.

2) Electric potential at d (2m) = -4000V

4) Kinetic energy = 0.5mv2 = 0.5(L)(v2)

K.E = 0.5(L)(v2) = -P.E = 8Ld (10-3)

3) v = (0.5/8d(10-3)) m/s

Note : i have done 3,4 parts assuming d= 2m is only for 2nd part .If you think its for the 3,4 pats also please substitute and you will get the answer.

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