The magnetic field through a 15 turn, 0.25 m radius coil varies with respect to
ID: 2063200 • Letter: T
Question
The magnetic field through a 15 turn, 0.25 m radius coil varies with respect to time according to the graph shown below. The field lines make an angle of 600 with respect to the coil plane.1.
a. What is the magnitude of the induced emf for the time interval 0 - 2 seconds?
b. What is the direction of the induced current during this time interval? (Counter Clockwise as seen from above, clockwise as seen from above, No current)
2.
a. What is the magnitude of the induced emf for the time interval 2 - 4 seconds?
b. What is the direction of the induced current during this time interval? (Counter Clockwise as seen from above, clockwise as seen from above, No current)
3.
a. What is the magnitude of the induced emf for the time interval 4 - 7 seconds?
b. What is the direction of the induced current during this time interval? (Counter Clockwise as seen from above, clockwise as seen from above, No current)
Image of Exercise: http://i44.tinypic.com/15hbez8.jpg
Thanks!
Explanation / Answer
(1)
=BAsin60
(at 0 s)= 0
(at 2 s)= 0.3**0.25^2*sin60
=0-0.3**0.25^2*sin60
=-0.0510131
Induced EMF = -N*/t
=0.3826 V
The direction on induced current is so that to oopose the change in magnetic field.
Hence, direction is clockwise as seen from above
(2)
(at 2 s)=0.3**0.25^2*sin60
(at 4 s)= 0.3**0.25^2*sin60
=0.3**0.25^2*sin60-0.3**0.25^2*sin60
=0
Induced EMF = -N*/t
=0 V
No current
(3)
=BAsin60
(at 7 s)= 0
(at 4 s)= 0.3**0.25^2*sin60
=0.3**0.25^2*sin60-0
=0.0510131
Induced EMF = N*/t
=0.2551 V
The direction on induced current is so that to oopose the change in magnetic field.
Hence, direction is Counter Clockwise as seen from above
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