Answers a) n=1.662 (use 90° for refracted ray in air) b) 48.75° c) ? (From 2011

Question

Answers

a) n=1.662   (use 90° for refracted ray in air)

b) 48.75°

c) ?

(From 2011 PHYS 122 exam) A glass-walled aquarium is filled with water and a ray of light traveling through the water strikes the glass wall as shown in the diagram. It is observed, when the angle theta 2 is increased to 37.0 degree, that the transmitted ray disappears (i.e., the light is total-internally-reflected at the glass-air interface). Determine the index of refraction of the glass? When theta 2 is at the critical angle (37.0 degree) for the glass-air interface, what is the angle theta 1? Is it possible for the reflected ray 1 to be totally internally reflected at the water- glass interface? Explain your answer.

Explanation / Answer

a.n1 sin 2 = 1* sin 90

2=37

n1 sin 37=1

n1=1/sin 37 =1.66

b.1.33 sin1 = 1.66*sin37

sin1 = 1/1.33

1=48.75

c.no for that

1.33 sin = 1.66 *sin90

sin = 1.24 which is not possible

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