The spin cycles of a washing machine have two angular speeds, 450 rev/min and 63

Question

The spin cycles of a washing machine have two angular speeds, 450 rev/min and 634rev/min . The internal diameter of the drum is 0.410 m.

What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed?

fhigher/flower=

What is the ratio of the maximum tangential speed of the laundry for the higher angular speed to that for the lower speed?

vhigher/vlower=

Find the laundry's maximum tangential speed .

vtan=

arad=

The spin cycles of a washing machine have two angular speeds, 450 rev/min and 634rev/min . The internal diameter of the drum is 0.410 m. What is the ratio of the maximum radial force on the laundry for the higher angular speed to that for the lower speed? fhigher/flower= What is the ratio of the maximum tangential speed of the laundry for the higher angular speed to that for the lower speed? vhigher/vlower= Find the laundry's maximum tangential speed . vtan= Find the laundry's maximum radial acceleration, in terms of {g} . arad=

Explanation / Answer

R = 0.41/2 = 0.205 m

1 = 2(450/60) = 47.1 rads

2 = 2(634/60) = 66.36 rads

(a) Force = ma = m2r

Max radial force = m2R

So, Fhigher/Flower = (higher/lower)2 = ( 66.36/47.1 )2 = 1.98

(b) Tangential speed, v = r

Max tangential speed, v = R

So, vhigher/vlower = (higher/lower) = 66.36/47.1 = 1.4

(c) Max tangential speed, vrad = higherR = 66.36*0.205 = 13.6 m/s

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