R x =N R y =N In an emergency situation, a person with a broken forearm ties a s

Question

Rx =N Ry =N In an emergency situation, a person with a broken forearm ties a strap from his hand to clip on his shoulder as in the figure below. His 1.60-kg forearm remains in a horizontal position and the strap makes an angle of?=49.5 with the horizontal. Assume the forearm is uniform, has a length of l =0.330m,assume the biceps muscle is relaxed, and ignore the mass and length of the hand. (a) Find the tension in the strap. N (b) Find the components of the reaction force exerted by the humerus on the forearm.

Explanation / Answer

torque =r1*W-r2*T

r1=r2=0.33m

W=1.6*9.8=15.68N

T=r1*W/r2sin49.5=W./sin49.5=20.63N

B)Rx =Tsin49.5=15.68N

Ry =Tcos49.5=13.39N

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