in a research studied involving a distant galaxy, an emission line of .700um was
ID: 2068023 • Letter: I
Question
in a research studied involving a distant galaxy, an emission line of .700um was found. This emission is found to be associated with an electron jumping from the n=3 to n=2 level in hydrogen atoms in the gas of the galaxy. Find how fast the galaxy is moving away from us and how far away the galaxy was when the light was emitted.
The .700um is what I am unsure what it stands for. I don't know if it is my of the observed or a frequency.
My knowns are
R= 1.097 x 10^7 m^-1
nf= 2
ni= 3
H= .022 m/s x lightyear
I found the of the source to = 656nm and using the formula f=c/ to get 457317 ( i am unsure if this is my observed freqency or the source of frequency. Can you please help with this as well. Thanks!
The reason I need to know is because I am trying to solve this equation.
fo=fs(1± (Vrel/c))
Explanation / Answer
'um' stands for micrometer.
1 um = 10-6 m
Thus 0.700 um is the observed wavelength. You can use it in you formula after changing to frequency.
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