An ac generator with Em = 239 V operating at 418 Hz causes oscillations in a ser

Question

An ac generator with Em = 239 V operating at 418 Hz causes oscillations in a series RLC circuit having R = 230 ohm, L = 110 mH, and C = 23.0 F. (a) Find the capacitive reactance XC. ohm (b) Find the impedance Z. ohm (c) Find the current amplitude I. A (d) A second capacitor of the same capacitance is then connected in series with the other components. How do these values change? (Select all that apply.) XC increases XC decreases XC remains the sameZ increasesZ decreasesZ remains the sameI increasesI decreasesI remains the same

Explanation / Answer

A) capacitive reactance XC = 1/C = 1/2*3.14*418*23*10^-6 = 16.56

b) IMPEDENCE Z = R^2+(XL-XC)^2

        XL = L = 2*3.14*418*110*10^-3 = 288.754

Z = 52900+74090.7 = 356.35

c) CURRENT I = /Z = 239/356.35 = 0.67 AMPS

d) xc DECREASES, Z INCREASES, I DECREASES

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