a parallel plate capacitor consisting of two square plates has a potential diffe

Question

a parallel plate capacitor consisting of two square plates has a potential difference V0 across the plates, and separated by a gap of 1.1mm. There is a vacuum between the plates. An electron real eased from rest at the surface of the negative plate crosses the capacitor and strikes the positive plate with a speed of
1.78*10^6 m/s. The charge on the electron is e= 1.6*10^-19 C and its
mass is me = 9.1*10^-31 kg.

What is the potential difference across the plates?

what is the magnitude of the electric field inside the capacitor?

Explanation / Answer

Conserve energy

qV=1/2m*vel^2

=>V= 9 Volts

Magnitude of field= V/d= 8.181 kilo V/m

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