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These must be completed in MATLAB Question 1. The velocity of a rocket is given

ID: 2074294 • Letter: T

Question

These must be completed in MATLAB

Question 1. The velocity of a rocket is given as:

where t is time in seconds and velocity is in meters per second.

Do the following and print the results to the Command Window:

1.    Create a vector for time, incremented by 0.5 seconds.

2.    Create a corresponding velocity vector.

3.    Find the velocity of the rocket at t = 8 s.

4.    Create a vector of the rocket's average acceleration

Question 2.

Given the following vector A and vector B

Do the following and print the results to the Command Window.

1.    Determine whether matrix multiplication of A and B (AB) is possible. Use the function size and a relational operator to make the determination.

2.    Find the resultant scalar, C, from matrix multiplication of A and B(C=AB).

3.    Transpose B and concatenate vectors A and B into a single vector, D. Replace the 5th element in D with the value 16.

4.    Find the dot product of the vectors A and B.

14* 104 v(t) = 2000ln( 7 =) — 9.8t (14* 104) - 2100t

Explanation / Answer

Question 1:

Matlab code

clear all;
clc;
close all;

i=0;

for t=0:0.5:10
i=i+1;
T(i,1)=t; %Creating a vector for time, incremented by 0.5 seconds.
  
V(i,1)=2000*log((14*10^4)/(14*10^4-2100*t)); %Creating a corresponding velocity vector.
  
if t==8 %Finding the velocity of the rocket at t = 8 s.
fprintf('Velocity of the rocket at t = 8 s is %f ',V(i,1))
  
end

end

dt=0.5;

for j=1:20

avgacceleration(j,1)=(V(j+1,1)-V(j,1))/dt; % Creating a vector of the rocket's average acceleration
end

Result:

Velocity of the rocket at t = 8 s is 255.666743

Question 2:


clear all;
clc;
close all;

A=[24 6 10];

x=size(A);

B=[3; 4; 13];

y=size(B);

if x(2)==y(1)
  
fprintf('Matrix multiplication is possible ')
C=A*B;
fprintf('The resultant scalar C, from matrix multiplication of A and B is %f ',C);
  
end
fprintf(' Transpose of matrix B is ')
Bt=B'
fprintf('concatenate of vectors A and B is ')
D = horzcat(A,Bt)
D(5)=16;
fprintf('after replacing 5th element matrix D is ')
D

fprintf('Dot product of vectors A and B is %f ',dot(A,B))

Reuslt:

Matrix multiplication is possible

The resultant scalar C, from matrix multiplication of A and B is 226.000000  

Transpose of matrix B is

Bt =

3 4 13

concatenate of vectors A and B is

D =

24 6 10 3 4 13

after replacing 5th element matrix D is


D =

24 6 10 3 16 13

Dot product of vectors A and B is 226.000000

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