please answer parts A and B. A V= 110-V source is connected in series with an R

Question

please answer parts A and B.

A V= 110-V source is connected in series with an R = 1.3 k-Ohm resistor and an L = 34-H inductor and the current is allowed to reach maximum. At tune t = 0 a switch is thrown that disconnects the voltage source, but leaves the resistor and the inductor connected m then own circuit. V=110V R = 1.3 k & Omega L = 34H (a) How much tune, in milliseconds, is needed for the current in the circuit to drop to 8 % of its value at t = 0? (b) How much energy, m, does the circuit dissipate during that time?

Explanation / Answer

Here ,

a) time constant , T = L/R

T = 34/1.3 ms

T = 26.2 ms

let the time taken is t

I = Io * e^(-t/T)

0.08 = e^(-t/26.2)

solving for t

t = 66.2 ms

the time taken is 66.2 ms

b)

for the energy in the circuit at that time

E = 0.50 * 34 * (110/(1.3 *10^-3) * 0.08)^2

E = 7.8 *10^-4 J = 0.78 mJ

the energy is 0.78 mJ

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