The two wires shown in the figure below are separated by d = 11.4 cm and carry c

Question

The two wires shown in the figure below are separated by d = 11.4 cm and carry currents of I = 5.25 A in opposite directions. (a) Find the magnitude and direction of the net magnetic field at a point midway between the wires. magnitude 30.84 direction (b) Find the magnitude and direction of the net magnetic field at point P_1, 11.4 cm to the right of the wire on the right. magnitude 4.6 mu T direction (c) Find the magnitude and direction of the net magnetic field at point P_1, 2d = 22.8 cm to the left of the wire on the left. magnitude 1.5 direction

Explanation / Answer

Here ,

a) at the midpoint

field at the midpoint = magnetic field due to wire 1 + magnetic field due to wire 2

field at the midpoint = 4pi *10^-7/(2pi) * (5.25/(0.114/2) + 5.25/(0.114/2))

field at the midpoint = 3.68 *10^-5 T

the field is into the page

b)

at the point P1

magnetic field at P1 = magnetic field due to right wire - magnetic field due to left wire

magnetic field at P1 = 4pi *10^-7/(2pi) * (5.25/(0.114) - 5.25/(2 * 0.114))

magnetic field at P1 = 4.61 *10^-6 T

the direction of field is out of the page

c)

at the point P2

magnetic field at P2 = -magnetic field due to right wire + magnetic field due to left wire

magnetic field at P2 = 4pi *10^-7/(2pi) * (5.25/(2 *0.114) + 5.25/(3 * 0.114))

magnetic field at P2 = 7.67 *10^-6 T

the direction of field is out of the page

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