Please show calculations! Thank you in advance! :) Problem 34.22 Part A A 4.0-cm

Question

Please show calculations!
Thank you in advance! :)

Problem 34.22 Part A A 4.0-cm tall object is placed 60 cm away from a converging lens of focal length 30 cm. What are the nature and location of the image? The image is virtual, 2.0 cm tall, and 15 cm from the lens on the side opposite the object. real, 4.0 cm tall, and 60 cm from the lens on the side opposite the object. virtual, 2.5 cm tall, and 30 cm from the lens on the side opposite the object. virtual, 4.0 cm tall, and 60 cm from the lens on the same side as the object. real, 2.5 cm tall, and 30 cm from the lens on the same side as the object.

Explanation / Answer

Apply 1/f = 1/p + 1/q

1/30 = 1/60 + 1/q

q = 60 cm

For the height

h'/h = q/p

h'/4 = 60/60

h = 4 cm

Since q is positive, the image is real, on the other side of the lens, and inverted.

The image is real. 4.0 cm tall, 60 cm on the side opposite to the object. (option B)

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