A charged ball is fired straight up, starting from a point at which the electric
ID: 2079503 • Letter: A
Question
A charged ball is fired straight up, starting from a point at which the electric potential is +200 V. The equipotentials are equally spaced, as shown in the picture below, with successive lines in the picture being exactly 1.00 meter apart. This is done at the surface of the Earth, where the gravitational field has a value of g = 10.0 m/s2, directed straight down. The ball has a mass of 200 grams, and the magnitude of the charge on the ball is 10 millicoulombs.
(a) In what direction is the electric field in this situation? (choose one)
It's directed to the right.
It's directed down.
It's directed vertically, but we can't tell whether it is up or down.
The direction of the field depends on whether the ball has a positive charge or a negative charge.
It's directed to the left.
It's directed up.
It's directed horizontally, but we can't tell whether it is left or right.
(b) If the ball has a positive charge, what initial velocity must it have at the +200-V level for it to reach its maximum height at the +400-V level?
(c) If the ball has a negative charge instead, what initial velocity must it have at the +200-V level for it to reach its maximum height at the +400-V level?
1.00 m 800 V 700 V 600 V 500 V 400 V 300 V 200 VExplanation / Answer
a) In what direction is the electric field in this situation? ans:it istowards down
b)If the ball has a positive charge instead, what initial velocity must it have at the +200-V level for it to reach its maximum height at the +400-V level? ans:11.8m/s
c)If the ball has a negative charge instead, what initial velocity must it have at the +200-V level for it to reach its maximum height at the +400-V level? ans:7.5m/s
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