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First order circuits pre - lab only PRELAB: ONLY DO NUMBER 1. FOR NUMBER 2 just

ID: 2082563 • Letter: F

Question

First order circuits pre - lab only

PRELAB:

ONLY DO NUMBER 1. FOR NUMBER 2 just hand calculate the period and time constant if you can. NUMBER 1 is most important though.

Calculation:

1. Consider the circuit in Fig 1. The square wave has amplitudes 5 V, 50% duty cycle (which means the pulse width is half of its period), frequency of 100 kHz. The built-in resistor Rs of function generator is 50 Ohm. The value of capacitor C is 1nF. Find the value of resistor R so that the time constant of this RC circuit is less than 1/10 of the pulse width.

2. Do the following simulations using pspice.

Use the conditions from 1, plot vs t and vs t only showing 2 periods.

Based on the result plot, what is the time constant?

21 First its (Prot rted Miaw Whrd File Home Insert Draw Design Layout Reterences Mailings Review view Tell me what you want to do Lab 3 First-order and Scco Order Circuits RC and RCL transient response Objective: lo study the step response of first order circuits Equipment: oscilloscope unction Generator Inductor Potentio meter Capacitor Part I: First-Order Circuits: Series RC circuit Background: Signal Figl a Consider the scrics RC circuit in a. The capacitor voltage is given by: The current in the loop can be found to be: w3 Type here to search Sign in M 2:09 PM 4/23/2011

Explanation / Answer

1. First of all I can not calculate the pulse width for bad picture quality. That does not matter let us take the present time constant is T.
   Now, this is a parallel RC circuit where time constant T=R*C
   The pulse width of the output is varies linearly with the time constant of the RC circuit.
   Thus simply changging the time constant the to one fifth of the previous value(as pulse width is half of the time constant) we can achieve our goal.
   Here total resistance is (R+50) and capacitance is C
   Thus according to the condition,
   T= 2*Pulse width and we have to make it, TT=pulse width /10 ie, new pulse width =20 * previous time constant
   (R+50)*C =(50)*C*20
   => R=1000-50=950Ohm