When switched off, the voltage across an inductor: Select one: a. rises rapidly

Question

When switched off, the voltage across an inductor: Select one: a. rises rapidly b. can't tell c. reverses d. rises slowly Two parallel current-carrying wires that are in close proximity to form a closed current path for a circuit, would: Select one: a. cause short circuits b. twist c. heat up rapidly d. push each other away If the insulation on an inductor breaks down, it can present problems including: Select one: a added turns b. poor resistance c. reduced effective inductance d. open circuits

Explanation / Answer

when switched off, the voltage across an inductor:

-->An inductor is an energy storing element, when an voltage is applied it stores energy in the form of electro magnetic field. when an switch is off or when the voltage is open the inductor gets reversed and gives the energy back.

So reverses is the answer.

-->when a current is flowing in a wire an flux is induced over the wire. so when two parallel wires are get to a close proximity to form a closed circuit for the current it causes short circuit in the both wires.

if the insulator on an inductor breaks down, it reduces the effective inductance of the inductor. because the inductor is used to provide insulation between the live conductor and ground. when such inductor's insulation get break it reduces the effective inductance.

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