A 12.6-uF capacitor is connected through a 0.895-M(Ohm) resistor to a constant p

Question

A 12.6-uF capacitor is connected through a 0.895-M(Ohm) resistor to a constant potential difference of 60.0 V. 1) Compute the charge on the capacitor at the following times after the connections are made: 0, 5.0 s, 10.0 s, 20.0 s, and 100.0 s. Express your answers using two significant figures. Enter your answers numerically separated by commas. 2) Compute the charging currents at the same instants. Express your answers using two significant figures. Enter your answers numerically separated by commas. *Show work and complete entire problem for full-rating.

Explanation / Answer

1) Q = Qo(1 - e^(-t/RC)

Use this equation to calculate the charges

at 0 s: Q = Qo = CE = 12.6 * 60 = 756 uC

at 5 s: Q = Qo(1 - e^(-5/12.6*.895)) = 270.75 uC

Similarly put the values and calculate the charges at each instant.

2) For calculating the current

I = Io e^(-t/RC)

Put the values and solve :) , if you have any doubts please ask I will give you the answers :)

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