So we start with 50g of steam at 105 degrees C added to 30g ice at -20 degrees C

Q: So we start with 50g of steam at 105 degrees C added to 30g ice at -20 degrees C

It means that 50-10.3g=39.7 g of steam condenses. This creates enough heat to heat ice to 0C, melt it, then heat the resulting water to 100C. Since heating the water anymore would result in it turning to steam, the rest of the steam remains in the steam state and the final temperature is 100C.

ID: 2092108 • Letter: S

Question

So we start with 50g of steam at 105 degrees C added to 30g ice at -20 degrees C. I drew out the diagram it should follow and using the equations I labeled them as, I came up with 300calories to warm ice to 20 degrees C, 2368 calories to melt all the ice, 3004 calories to warm the ice water to 100 degrees C, -120.2 calories to cool steam 5 degrees C, -27033 calories to condense all the steam and -5007 calories to cool steam water to 0 degrees C. I then plugged it into this equation: M_ice C_ice ?T+M_ice L_f+M_(ice water) C_(ice water) ?T- M_steam C_steam ?T-M_steam L_v=0 and got: (0.03kg)(2090 ?(J/(Kg ??)))(20?)+(0.030kg)(3.3x10^5 ?(J/kg))+(0.030kg)(4186 ?(J/(Kg ??)))(100?)- (0.05kg)(2010 J/(Kg ??))(5?)-M_steam (2.26x10^6 ?(J/kg))=0 With the mass of the steam being: M_steam=10.3g I know all these values are right, but when I'm trying to evaluate what the 10.3 grams means, my head hurts....Because at the beginning of the problem, it says that the mass of the steam is 50grams, so why did i end up with 10.3g? The problem says there can be three possible endings: 1) not all the steam condenses, 2)Not all the ice melts and 3) T final is between 0 and 100degrees C. Then it asks: can T final be = to 100 degrees C?, Can T final = 0?, and can 0<T final <100? It says the only possible one is T final =100, but WHYYYYY...... So basically, I am asking what does the 10.3 grams of steam mean, and why is it possibly that T final be equal to 100 degrees C. Please make it as simple as possible....Thank you!

Explanation / Answer

It means that 50-10.3g=39.7 g of steam condenses.

This creates enough heat to heat ice to 0C, melt it, then heat the resulting water to 100C. Since heating the water anymore would result in it turning to steam, the rest of the steam remains in the steam state and the final temperature is 100C.

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So we start with 50g of steam at 105 degrees C added to 30g ice at -20 degrees C

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