A 5.95-mm-high firefly sits on the axis of, and 13.9 cm in front of, the thin le

Question

A 5.95-mm-high firefly sits on the axis of, and 13.9 cm in front of, the thin lens A, whose focal length is 6.03 cm. Behind lens A there is another thin lens, lens B, with focal length 26.5 cm. The two lenses share a common axis and are 56.1 cm apart. Is the image of the firefly that lens B forms real or virtual?How far from lens B is this image located (expressed as a positive number)?What is the height of this image (as a positive number)?Is this image upright or inverted with respect to the firefly?

Explanation / Answer

1/f=1/d0+1/d
for first lens

1/5.89=1/13.9+1/d

d=10.2210986267cm from first lens

d01 for second lens=56.1--10.221=45.879cm

1/f1=1/d01+1/d1
1/26.5=1/45.879+1/d1

d1=62.7376799628cm from the second lens(ans)
upright

m1=10.221/13.9=0.7353237410071942=h2/5.95
height from first lens

h2=h1*.7353=4.375035mm
foe lensB
m2=62.737/45.879=h3/h2
h3=5.982571001983478mm(ans)

after two lens converging take place

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