A cylinder with radius r 1 = 1.15m has a hole through the side with a net mass m

Question

A cylinder with radius r1= 1.15m has a hole through the side with a net mass m1= 5.02kg. A longer but radially smaller cylinder is then stuck through the hole in the radially larger cylinder as shown in the above diagram. The mass of the longer cylinder is m2= 4.95kg and has a radius of r2= 0.237m. The center of the long cylinder is a distance of R = r1- r2from the center of the shorter but radially larger cylinder. What is the torque on the object when we apply an angular acceleration of ? = 3.05rad/s2about the center axis of the longer (radially small) cylinder?

Answer inkg m2/s2

Explanation / Answer

I of system = 4.95 x 0.237^2/2 + [ 5.02 x 1.15^2 /2 + 5.02 x (1.15 - 0.237)^2]

I = 7.64 kg.m^2

torqu = I x angular acceleration = 7.64 x 3.05 = 23.31 kgm^2/s^2

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