A cylinder with radius r 1 = 1.15m has a hole through the side with a net mass m

Question

A cylinder with radius r1 = 1.15m has a hole through the side with a net mass m1 = 5.02kg. A longer but radially smaller cylinder is then stuck through the hole in the radially larger cylinder as shown in the above diagram. The mass of the longer cylinder is m2 = 4.95kg and has a radius of r2 = 0.237m. The center of the long cylinder is a distance of R = r1 - r2 from the center of the shorter but radially larger cylinder. What is the angular momentum of the system when we apply an angular velocity of ? = 3.05rad/s about the center axis of the longer cylinder?

Explanation / Answer

angular momentum of the system L= IW

I =[Mrod*r1^2/2]+[Mdisk*(r1-r2)^2/2]

L =6.8 kgm^2s^-1

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