A cylinder with radius r 1 = 1.15m has a hole through the side with a net mass m

Question

A cylinder with radius r1 = 1.15m has a hole through the side with a net mass m1 = 5.02kg. A longer but radially smaller cylinder is then stuck through the hole in the radially larger cylinder as shown in the above diagram. The mass of the longer cylinder is m2 = 4.95kg and has a radius of r2 = 0.237m. The center of the long cylinder is a distance of R = r1 - r2 from the center of the shorter but radially larger cylinder. What is the angular momentum of the system when we apply an angular velocity of ? = 3.05rad/s about the center axis of the longer cylinder?

Explanation / Answer

Inet = 4.95 x 0.237^2/2 + 5.02 x 1.15^2/2 + 5.02 x (1.15 - 0.237)^2 = 7.64 Kg.m^2

angular momentum = Iw = 7.64 x 3.05 =23.31 kg.m^2/2

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