a gymnast with a mass of 58.5 kg does a handstand 1.00 m from the end of a 2.4 m

Question

a gymnast with a mass of 58.5 kg does a handstand 1.00 m from the end of a 2.4 m long balance beam. the balance beam has a mass of 155 kg and is resting on two supports, one on each end.

a) what is the magnitude of the force the the left side support exerts on the balance beam? (the support closest to the gymnast)

b) what is the magnitude of the force the the right side support exerts on the balance beam? (the support farthest from the gymnast)

please include detailed step by step solutions including which equations used. thanks!

Explanation / Answer

Part A)

Balance the torques using the right support as the Pivot Point

(58.5)(9.8)(1.4) + (155)(9.8)(1.2) = (F)(2.4)

F = 1094 N

Part B)

All of the downward forces must equal the upward

(58.5)(9.8) + (155)(9.8) = (1094) + F

F = 998.3 N

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