The yellow component of light from a helium discharge tube (lambda = 587.5) is a
ID: 2095177 • Letter: T
Question
The yellow component of light from a helium discharge tube (lambda = 587.5) is allowed to fall on a plate containing parallel slits that are 0.2 mm apart. A screen is positioned so that the second bright fringe in the interference pattern is a distance equal to 10 slit spacing from the central maximum. What is the distance between teh plate and the screen? The answer is 34 cm.
lambda = 587.5x 10^-9m d= .2 x 10^-3m
y = 10d (or 2) D = ?
I started with y = lamda D/2d, but came up with the wrong answer. Thanks for the help!
Explanation / Answer
lambda = x*d/nL
where x is the distance from the central fringe
lambda = x*.2*10^-3/10*L
what
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