The x, y, and z components of a magnetic field are Bx = 0.13 T, By = 0.16 T, and
ID: 2175388 • Letter: T
Question
The x, y, and z components of a magnetic field are Bx = 0.13 T, By = 0.16 T, and Bz = 0.17 T. A 25 cm wire is oriented along the z axis and carries a current of 5.1 A. What is the magnitude of the magnetic force that acts on this wire?N
Explanation / Answer
Relevant equations F=ILB (sin theta) a^2 + b^2 = c^2 3. The attempt at a solution Well, I have F= (4.5A)(0.25 m)(B?????) (sin theta) Ok, so I know what I and L are--> 4.5 A and 0.25 m. I also know that B is going to be the vector sum of components x and y--> 0.10^2 + 0.13^2 = B^2, which gives me B= 0.16. I did not include z because the current is in the z direction (parallel direction = 0, since sin 0 = 0). My question is: How do I find theta? Theta is the angle between the current and the magnetic field. I know the magnetic field = 0.16 and the direction of the current is in the z-axis, which is 0.17. I was thinking of doing the tan inverse of 0.16/0.17, but I don't think that answer is right.
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