A particle with charge 94.5 n C is moving in the region where there is a uniform

Question

A particle with charge 94.5 n C is moving in the region where there is a uniform magnetic field of magnitude 0.45 T pointing in the negative x-direction. At a particular instant of time the velocity of the particle has components: v x = - 1 .6 8 Times 10 m/s, v y = - 3.11 Times 1 0 4 m/s, and Vz = 5.85 Times 1 0 4 m/s. What is the magnetic field vector? Your answer must be in vector form. What is the velocity vector of the particle? Your answer must be in vector form. What is the force on the particle at this time? Your answer must be in vector form, i.e., zero points will be assigned if the force is not in the vector form.

Explanation / Answer

a) B= -0.45i T

b) V= (-1.68i -3.11j +5.85k )*10^4 m/s

c) F=q(v X B) = (-2.63j-1.39 k)*94.5*10^-5N

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