A charge Q 1 = 0.0299 ?C is located a distance d = 3.74 cm to the left of anothe

Question

A charge Q1 = 0.0299 ?C is located a distance d = 3.74 cm to the left of another charge Q2 = - 0.021 ?C.
a. At what point along the line joining the charges is the electric field zero? Give your answer as the distance x from the charge Q2, positive if the point lies to the right of Q2 and negative if to the left.

b. At what two points along the line joining the charges is the electric potential zero? Again give the distance x from the charge Q2, positive if the point lies to the right of Q2 and negative if to the left. Leftmost point x1=? Rightmost point x2?

Please include how to obtain the answer ( how to go about solivng this) and not just the answer.

Explanation / Answer

will have to be on the right of Q2 since there directions are oppositve

E1 = E2

k 0.0299 uC /(x + 3.74E-2)^2 = k*0.021uC/x^2

0.0299 x^2 = 0.021*(x+3.74E-2)^2

x=0.194 m

b)

V1 = V2

k 0.0299 uC /(x + 3.74E-2)= k*0.021uC/x

0.0299 x = 0.021 * (x+3.74E-2)

x=0.0882 m

if to the left

k 0.0299 uC /(3.74E-2-x)= k*0.021uC/x

0.0299 x = 0.021 * (3.74E-2-x)

x=-0.0154 m

neg means to the left

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