In the figure here, a solid brass ball of mass 0.108 g will roll smoothly along

Question

In the figure here, a solid brass ball of mass 0.108 g will roll smoothly along a loop-the-loop track when released from rest along the straight section. The circular loop has radius R = 0.19 m, and the ball has radius r << R. (a) What is h if the ball is on the verge of leaving the track when it reaches the top of the loop? (b) If the ball is released at height h = 7R, what is the magnitude of the horizontal force component acting on the ball at point Q? http://edugen.wileyplus.com/edugen/courses/crs4957/art/qb/qu/c11/qu11_a.jpg

Explanation / Answer

v at top= sqrt(Rg)

mgh=m*v^2/2 +2mgR

=>h=5R/2=0.475m

now energy conservation

h=7R

7mgR=mv^2/2+mgR

v=sqrt(12gR)=4.72 m

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.